6=2(j-5)

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Solution for 6=2(j-5) equation: 



6=2(j-5)

We move all terms to the left:

6-(2(j-5))=0



We calculate terms in parentheses: -(2(j-5)), so:

2(j-5)

We multiply parentheses

2j-10

Back to the equation:

-(2j-10)



We get rid of parentheses

-2j+10+6=0

We add all the numbers together, and all the variables

-2j+16=0

We move all terms containing j to the left, all other terms to the right

-2j=-16

j=-16/-2

j=+8

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