6=2(t*t)+4t+8

Solution for 6=2(t*t)+4t+8 equation:

6=2(t*t)+4t+8

We move all terms to the left:

6-(2(t*t)+4t+8)=0

We add all the numbers together, and all the variables

-(2(+t*t)+4t+8)+6=0


We calculate terms in parentheses: -(2(+t*t)+4t+8), so:

2(+t*t)+4t+8

We add all the numbers together, and all the variables

4t+2(+t*t)+8

We multiply parentheses

2t^2+4t+8

Back to the equation:

-(2t^2+4t+8)


We get rid of parentheses

-2t^2-4t-8+6=0

We add all the numbers together, and all the variables

-2t^2-4t-2=0

a = -2; b = -4; c = -2;
Δ = b2-4ac
Δ = -42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{4}{-4}=-1$