6=2(u+6)+4u

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Solution for 6=2(u+6)+4u equation: 



6=2(u+6)+4u

We move all terms to the left:

6-(2(u+6)+4u)=0



We calculate terms in parentheses: -(2(u+6)+4u), so:

2(u+6)+4u

We add all the numbers together, and all the variables

4u+2(u+6)

We multiply parentheses

4u+2u+12

We add all the numbers together, and all the variables

6u+12

Back to the equation:

-(6u+12)



We get rid of parentheses

-6u-12+6=0

We add all the numbers together, and all the variables

-6u-6=0

We move all terms containing u to the left, all other terms to the right

-6u=6

u=6/-6

u=-1

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