6=2(z+2)

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Solution for 6=2(z+2) equation: 



6=2(z+2)

We move all terms to the left:

6-(2(z+2))=0



We calculate terms in parentheses: -(2(z+2)), so:

2(z+2)

We multiply parentheses

2z+4

Back to the equation:

-(2z+4)



We get rid of parentheses

-2z-4+6=0

We add all the numbers together, and all the variables

-2z+2=0

We move all terms containing z to the left, all other terms to the right

-2z=-2

z=-2/-2

z=1

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