6=2+(y+2)

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Solution for 6=2+(y+2) equation: 



6=2+(y+2)

We move all terms to the left:

6-(2+(y+2))=0



We calculate terms in parentheses: -(2+(y+2)), so:

2+(y+2)

determiningTheFunctionDomain
(y+2)+2

We get rid of parentheses

y+2+2

We add all the numbers together, and all the variables

y+4

Back to the equation:

-(y+4)



We get rid of parentheses

-y-4+6=0

We add all the numbers together, and all the variables

-1y+2=0

We move all terms containing y to the left, all other terms to the right

-y=-2

y=-2/-1

y=+2

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