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6=2/3(2-x)
We move all terms to the left:
6-(2/3(2-x))=0
Domain of the equation: 3(2-x))!=0We add all the numbers together, and all the variables
x∈R
-(2/3(-1x+2))+6=0
We multiply all the terms by the denominator
-(2+6*3(-1x+2))=0
We calculate terms in parentheses: -(2+6*3(-1x+2)), so:
2+6*3(-1x+2)
determiningTheFunctionDomain 6*3(-1x+2)+2
Wy multiply elements
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We use the square of the difference formula
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Back to the equation:
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