6=2/7(2x+28)

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Solution for 6=2/7(2x+28) equation: 



6=2/7(2x+28)

We move all terms to the left:

6-(2/7(2x+28))=0



Domain of the equation: 7(2x+28))!=0

x∈R



We multiply all the terms by the denominator


-(2+6*7(2x+28))=0



We calculate terms in parentheses: -(2+6*7(2x+28)), so:

2+6*7(2x+28)

determiningTheFunctionDomain
6*7(2x+28)+2

Wy multiply elements

42x(2+2

Back to the equation:

-(42x(2+2)



We add all the numbers together, and all the variables

-(42x4=0

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