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6=2x+2/2x+3
We move all terms to the left:
6-(2x+2/2x+3)=0
Domain of the equation: 2x+3)!=0We get rid of parentheses
x∈R
-2x-2/2x-3+6=0
We multiply all the terms by the denominator
-2x*2x-3*2x+6*2x-2=0
Wy multiply elements
-4x^2-6x+12x-2=0
We add all the numbers together, and all the variables
-4x^2+6x-2=0
a = -4; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·(-4)·(-2)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*-4}=\frac{-8}{-8} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*-4}=\frac{-4}{-8} =1/2 $
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