6=3(4c-2)

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Solution for 6=3(4c-2) equation:



6=3(4c-2)
We move all terms to the left:
6-(3(4c-2))=0
We calculate terms in parentheses: -(3(4c-2)), so:
3(4c-2)
We multiply parentheses
12c-6
Back to the equation:
-(12c-6)
We get rid of parentheses
-12c+6+6=0
We add all the numbers together, and all the variables
-12c+12=0
We move all terms containing c to the left, all other terms to the right
-12c=-12
c=-12/-12
c=1

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