6=3(4c-2)

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Solution for 6=3(4c-2) equation: 



6=3(4c-2)

We move all terms to the left:

6-(3(4c-2))=0



We calculate terms in parentheses: -(3(4c-2)), so:

3(4c-2)

We multiply parentheses

12c-6

Back to the equation:

-(12c-6)



We get rid of parentheses

-12c+6+6=0

We add all the numbers together, and all the variables

-12c+12=0

We move all terms containing c to the left, all other terms to the right

-12c=-12

c=-12/-12

c=1

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