6=3(b-12)

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Solution for 6=3(b-12) equation: 



6=3(b-12)

We move all terms to the left:

6-(3(b-12))=0



We calculate terms in parentheses: -(3(b-12)), so:

3(b-12)

We multiply parentheses

3b-36

Back to the equation:

-(3b-36)



We get rid of parentheses

-3b+36+6=0

We add all the numbers together, and all the variables

-3b+42=0

We move all terms containing b to the left, all other terms to the right

-3b=-42

b=-42/-3

b=+14

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