6=3(z+1)

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Solution for 6=3(z+1) equation:



6=3(z+1)
We move all terms to the left:
6-(3(z+1))=0
We calculate terms in parentheses: -(3(z+1)), so:
3(z+1)
We multiply parentheses
3z+3
Back to the equation:
-(3z+3)
We get rid of parentheses
-3z-3+6=0
We add all the numbers together, and all the variables
-3z+3=0
We move all terms containing z to the left, all other terms to the right
-3z=-3
z=-3/-3
z=1

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