6=3x+6/x+1/x

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Solution for 6=3x+6/x+1/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6 = 3*x+6/x+1/x // - 3*x+6/x+1/x

6-(3*x)-(6/x)-(1/x) = 0

6-3*x-6*x^-1-x^-1 = 0

6*x^0-3*x^1-7*x^-1 = 0

(6*x^1-3*x^2-7*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^1-3*x^2-7*x^0) = 0

x^1

6*x-3*x^2-7 = 0

6*x-3*x^2-7 = 0

DELTA = 6^2-(-7*(-3)*4)

DELTA = -48

DELTA < 0

x in { } 

x belongs to the empty set

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