6=3z+12

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Solution for 6=3z+12 equation: 



6=3z+12

We move all terms to the left:

6-(3z+12)=0

We get rid of parentheses

-3z-12+6=0

We add all the numbers together, and all the variables

-3z-6=0

We move all terms containing z to the left, all other terms to the right

-3z=6

z=6/-3

z=-2

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