6=4(2-k)=3k

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Solution for 6=4(2-k)=3k equation: 



6=4(2-k)=3k

We move all terms to the left:

6-(4(2-k))=0

We add all the numbers together, and all the variables

-(4(-1k+2))+6=0



We calculate terms in parentheses: -(4(-1k+2)), so:

4(-1k+2)

We multiply parentheses

-4k+8

Back to the equation:

-(-4k+8)



We get rid of parentheses

4k-8+6=0

We add all the numbers together, and all the variables

4k-2=0

We move all terms containing k to the left, all other terms to the right

4k=2

k=2/4

k=1/2

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