6=4/3(2)+b

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Solution for 6=4/3(2)+b equation: 



6=4/3(2)+b

We move all terms to the left:

6-(4/3(2)+b)=0



Domain of the equation: 32+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-32

b!=-32/1

b!=-32

b∈R



We add all the numbers together, and all the variables

-(+b+4/32)+6=0

We get rid of parentheses

-b+6-4/32=0

We multiply all the terms by the denominator


-b*32-4+6*32=0

We add all the numbers together, and all the variables

-b*32+188=0

Wy multiply elements

-32b+188=0

We move all terms containing b to the left, all other terms to the right

-32b=-188

b=-188/-32

b=5+7/8

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