6=6(u+2)-8u

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Solution for 6=6(u+2)-8u equation: 



6=6(u+2)-8u

We move all terms to the left:

6-(6(u+2)-8u)=0



We calculate terms in parentheses: -(6(u+2)-8u), so:

6(u+2)-8u

We add all the numbers together, and all the variables

-8u+6(u+2)

We multiply parentheses

-8u+6u+12

We add all the numbers together, and all the variables

-2u+12

Back to the equation:

-(-2u+12)



We get rid of parentheses

2u-12+6=0

We add all the numbers together, and all the variables

2u-6=0

We move all terms containing u to the left, all other terms to the right

2u=6

u=6/2

u=3

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