6=9(k+3)

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Solution for 6=9(k+3) equation: 



6=9(k+3)

We move all terms to the left:

6-(9(k+3))=0



We calculate terms in parentheses: -(9(k+3)), so:

9(k+3)

We multiply parentheses

9k+27

Back to the equation:

-(9k+27)



We get rid of parentheses

-9k-27+6=0

We add all the numbers together, and all the variables

-9k-21=0

We move all terms containing k to the left, all other terms to the right

-9k=21

k=21/-9

k=-2+1/3

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