6=k-32/10

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Solution for 6=k-32/10 equation:



6=k-32/10
We move all terms to the left:
6-(k-32/10)=0
We add all the numbers together, and all the variables
-(+k-32/10)+6=0
We get rid of parentheses
-k+6+32/10=0
We multiply all the terms by the denominator
-k*10+32+6*10=0
We add all the numbers together, and all the variables
-k*10+92=0
Wy multiply elements
-10k+92=0
We move all terms containing k to the left, all other terms to the right
-10k=-92
k=-92/-10
k=9+1/5

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