6=k-32/10

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Solution for 6=k-32/10 equation: 



6=k-32/10

We move all terms to the left:

6-(k-32/10)=0

We add all the numbers together, and all the variables

-(+k-32/10)+6=0

We get rid of parentheses

-k+6+32/10=0

We multiply all the terms by the denominator


-k*10+32+6*10=0

We add all the numbers together, and all the variables

-k*10+92=0

Wy multiply elements

-10k+92=0

We move all terms containing k to the left, all other terms to the right

-10k=-92

k=-92/-10

k=9+1/5

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