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6=w(5w+7)
We move all terms to the left:
6-(w(5w+7))=0
We calculate terms in parentheses: -(w(5w+7)), so:We get rid of parentheses
w(5w+7)
We multiply parentheses
5w^2+7w
Back to the equation:
-(5w^2+7w)
-5w^2-7w+6=0
a = -5; b = -7; c = +6;
Δ = b2-4ac
Δ = -72-4·(-5)·6
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-13}{2*-5}=\frac{-6}{-10} =3/5 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+13}{2*-5}=\frac{20}{-10} =-2 $
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