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6=x(1-2x)
We move all terms to the left:
6-(x(1-2x))=0
We add all the numbers together, and all the variables
-(x(-2x+1))+6=0
We calculate terms in parentheses: -(x(-2x+1)), so:We get rid of parentheses
x(-2x+1)
We multiply parentheses
-2x^2+x
Back to the equation:
-(-2x^2+x)
2x^2-x+6=0
We add all the numbers together, and all the variables
2x^2-1x+6=0
a = 2; b = -1; c = +6;
Δ = b2-4ac
Δ = -12-4·2·6
Δ = -47
Delta is less than zero, so there is no solution for the equation
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