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6=x(5-x)
We move all terms to the left:
6-(x(5-x))=0
We add all the numbers together, and all the variables
-(x(-1x+5))+6=0
We calculate terms in parentheses: -(x(-1x+5)), so:We get rid of parentheses
x(-1x+5)
We multiply parentheses
-1x^2+5x
Back to the equation:
-(-1x^2+5x)
1x^2-5x+6=0
We add all the numbers together, and all the variables
x^2-5x+6=0
a = 1; b = -5; c = +6;
Δ = b2-4ac
Δ = -52-4·1·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-1}{2*1}=\frac{4}{2} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+1}{2*1}=\frac{6}{2} =3 $
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