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6=x3(12-12x)
We move all terms to the left:
6-(x3(12-12x))=0
We add all the numbers together, and all the variables
-(x3(-12x+12))+6=0
We calculate terms in parentheses: -(x3(-12x+12)), so:
x3(-12x+12)
We multiply parentheses
-12x^4+12x^3
We do not support expression: x^4
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