6=y(8-2y)

Solution for 6=y(8-2y) equation:

6=y(8-2y)

We move all terms to the left:

6-(y(8-2y))=0

We add all the numbers together, and all the variables

-(y(-2y+8))+6=0


We calculate terms in parentheses: -(y(-2y+8)), so:

y(-2y+8)

We multiply parentheses

-2y^2+8y

Back to the equation:

-(-2y^2+8y)


We get rid of parentheses

2y^2-8y+6=0

a = 2; b = -8; c = +6;
Δ = b2-4ac
Δ = -82-4·2·6
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*2}=\frac{4}{4}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*2}=\frac{12}{4}
=3
$