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6X(2X+3)=X
We move all terms to the left:
6X(2X+3)-(X)=0
We add all the numbers together, and all the variables
-1X+6X(2X+3)=0
We multiply parentheses
12X^2-1X+18X=0
We add all the numbers together, and all the variables
12X^2+17X=0
a = 12; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·12·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*12}=\frac{-34}{24} =-1+5/12 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*12}=\frac{0}{24} =0 $
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