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6X(X+2)=6X+12
We move all terms to the left:
6X(X+2)-(6X+12)=0
We multiply parentheses
6X^2+12X-(6X+12)=0
We get rid of parentheses
6X^2+12X-6X-12=0
We add all the numbers together, and all the variables
6X^2+6X-12=0
a = 6; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·6·(-12)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*6}=\frac{-24}{12} =-2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*6}=\frac{12}{12} =1 $
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