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6X^2+28X-10=0
a = 6; b = 28; c = -10;
Δ = b2-4ac
Δ = 282-4·6·(-10)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-32}{2*6}=\frac{-60}{12} =-5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+32}{2*6}=\frac{4}{12} =1/3 $
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