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6X^2=76=3X^3+8X^2-321
We move all terms to the left:
6X^2-(76)=0
a = 6; b = 0; c = -76;
Δ = b2-4ac
Δ = 02-4·6·(-76)
Δ = 1824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1824}=\sqrt{16*114}=\sqrt{16}*\sqrt{114}=4\sqrt{114}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{114}}{2*6}=\frac{0-4\sqrt{114}}{12} =-\frac{4\sqrt{114}}{12} =-\frac{\sqrt{114}}{3} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{114}}{2*6}=\frac{0+4\sqrt{114}}{12} =\frac{4\sqrt{114}}{12} =\frac{\sqrt{114}}{3} $
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