6a(3a+8)=0

Solution for 6a(3a+8)=0 equation:

6a(3a+8)=0

We multiply parentheses

18a^2+48a=0

a = 18; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·18·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*18}=\frac{-96}{36}
=-2+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*18}=\frac{0}{36}
=0
$