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6a+12=2/1(3a-8)
We move all terms to the left:
6a+12-(2/1(3a-8))=0
Domain of the equation: 1(3a-8))!=0We multiply all the terms by the denominator
a∈R
6a*1(3a-8))-(2+12*1(3a-8))=0
Wy multiply elements
6a^2(3+12a(3=0
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