6a-40=4(1+7a)

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Solution for 6a-40=4(1+7a) equation: 



6a-40=4(1+7a)

We move all terms to the left:

6a-40-(4(1+7a))=0

We add all the numbers together, and all the variables

6a-(4(7a+1))-40=0



We calculate terms in parentheses: -(4(7a+1)), so:

4(7a+1)

We multiply parentheses

28a+4

Back to the equation:

-(28a+4)



We get rid of parentheses

6a-28a-4-40=0

We add all the numbers together, and all the variables

-22a-44=0

We move all terms containing a to the left, all other terms to the right

-22a=44

a=44/-22

a=-2

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