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6a/5a=a
We move all terms to the left:
6a/5a-(a)=0
Domain of the equation: 5a!=0We add all the numbers together, and all the variables
a!=0/5
a!=0
a∈R
-1a+6a/5a=0
We multiply all the terms by the denominator
-1a*5a+6a=0
We add all the numbers together, and all the variables
6a-1a*5a=0
Wy multiply elements
-5a^2+6a=0
a = -5; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-5)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-5}=\frac{-12}{-10} =1+1/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-5}=\frac{0}{-10} =0 $
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