6a2+-3.6a=0

Solution for 6a2+-3.6a=0 equation:

6a^2+-3.6a=0

We add all the numbers together, and all the variables

6a^2-3.6a=0

a = 6; b = -3.6; c = 0;
Δ = b2-4ac
Δ = -3.62-4·6·0
Δ = 12.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.6)-\sqrt{12.96}}{2*6}=\frac{3.6-\sqrt{12.96}}{12}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.6)+\sqrt{12.96}}{2*6}=\frac{3.6+\sqrt{12.96}}{12}
$