6b+27=3(5b-2)

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Solution for 6b+27=3(5b-2) equation:



6b+27=3(5b-2)
We move all terms to the left:
6b+27-(3(5b-2))=0
We calculate terms in parentheses: -(3(5b-2)), so:
3(5b-2)
We multiply parentheses
15b-6
Back to the equation:
-(15b-6)
We get rid of parentheses
6b-15b+6+27=0
We add all the numbers together, and all the variables
-9b+33=0
We move all terms containing b to the left, all other terms to the right
-9b=-33
b=-33/-9
b=3+2/3

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