6b+32=-4+3(b+8)

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Solution for 6b+32=-4+3(b+8) equation: 



6b+32=-4+3(b+8)

We move all terms to the left:

6b+32-(-4+3(b+8))=0



We calculate terms in parentheses: -(-4+3(b+8)), so:

-4+3(b+8)

determiningTheFunctionDomain
3(b+8)-4

We multiply parentheses

3b+24-4

We add all the numbers together, and all the variables

3b+20

Back to the equation:

-(3b+20)



We get rid of parentheses

6b-3b-20+32=0

We add all the numbers together, and all the variables

3b+12=0

We move all terms containing b to the left, all other terms to the right

3b=-12

b=-12/3

b=-4

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