6b+5=(3-b)4

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Solution for 6b+5=(3-b)4 equation: 



6b+5=(3-b)4

We move all terms to the left:

6b+5-((3-b)4)=0

We add all the numbers together, and all the variables

6b-((-1b+3)4)+5=0



We calculate terms in parentheses: -((-1b+3)4), so:

(-1b+3)4

We multiply parentheses

-4b+12

Back to the equation:

-(-4b+12)



We get rid of parentheses

6b+4b-12+5=0

We add all the numbers together, and all the variables

10b-7=0

We move all terms containing b to the left, all other terms to the right

10b=7

b=7/10

b=7/10

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