6b+6(b+2)=108

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Solution for 6b+6(b+2)=108 equation: 



6b+6(b+2)=108

We move all terms to the left:

6b+6(b+2)-(108)=0

We multiply parentheses

6b+6b+12-108=0

We add all the numbers together, and all the variables

12b-96=0

We move all terms containing b to the left, all other terms to the right

12b=96

b=96/12

b=8

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