6b-(b+2)+(-b+3)=15b-10=

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Solution for 6b-(b+2)+(-b+3)=15b-10= equation: 



6b-(b+2)+(-b+3)=15b-10=

We move all terms to the left:

6b-(b+2)+(-b+3)-(15b-10)=0

We add all the numbers together, and all the variables

6b-(b+2)+(-1b+3)-(15b-10)=0

We get rid of parentheses

6b-b-1b-15b-2+3+10=0

We add all the numbers together, and all the variables

-11b+11=0

We move all terms containing b to the left, all other terms to the right

-11b=-11

b=-11/-11

b=1

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