6b-10=2(b-11)+4(b-2)

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Solution for 6b-10=2(b-11)+4(b-2) equation: 



6b-10=2(b-11)+4(b-2)

We move all terms to the left:

6b-10-(2(b-11)+4(b-2))=0



We calculate terms in parentheses: -(2(b-11)+4(b-2)), so:

2(b-11)+4(b-2)

We multiply parentheses

2b+4b-22-8

We add all the numbers together, and all the variables

6b-30

Back to the equation:

-(6b-30)



We get rid of parentheses

6b-6b+30-10=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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