6b-11b=-10(-1+b)+3(1+2b)

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Solution for 6b-11b=-10(-1+b)+3(1+2b) equation: 



6b-11b=-10(-1+b)+3(1+2b)

We move all terms to the left:

6b-11b-(-10(-1+b)+3(1+2b))=0

We add all the numbers together, and all the variables

6b-11b-(-10(b-1)+3(2b+1))=0

We add all the numbers together, and all the variables

-5b-(-10(b-1)+3(2b+1))=0



We calculate terms in parentheses: -(-10(b-1)+3(2b+1)), so:

-10(b-1)+3(2b+1)

We multiply parentheses

-10b+6b+10+3

We add all the numbers together, and all the variables

-4b+13

Back to the equation:

-(-4b+13)



We get rid of parentheses

-5b+4b-13=0

We add all the numbers together, and all the variables

-1b-13=0

We move all terms containing b to the left, all other terms to the right

-b=13

b=13/-1

b=-13

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