6b-2(2-b)=4(2b-1)

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Solution for 6b-2(2-b)=4(2b-1) equation:



6b-2(2-b)=4(2b-1)
We move all terms to the left:
6b-2(2-b)-(4(2b-1))=0
We add all the numbers together, and all the variables
6b-2(-1b+2)-(4(2b-1))=0
We multiply parentheses
6b+2b-(4(2b-1))-4=0
We calculate terms in parentheses: -(4(2b-1)), so:
4(2b-1)
We multiply parentheses
8b-4
Back to the equation:
-(8b-4)
We add all the numbers together, and all the variables
8b-(8b-4)-4=0
We get rid of parentheses
8b-8b+4-4=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0

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