6b-27=3(5b-2)

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Solution for 6b-27=3(5b-2) equation: 



6b-27=3(5b-2)

We move all terms to the left:

6b-27-(3(5b-2))=0



We calculate terms in parentheses: -(3(5b-2)), so:

3(5b-2)

We multiply parentheses

15b-6

Back to the equation:

-(15b-6)



We get rid of parentheses

6b-15b+6-27=0

We add all the numbers together, and all the variables

-9b-21=0

We move all terms containing b to the left, all other terms to the right

-9b=21

b=21/-9

b=-2+1/3

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