6b-3+b+1=-5(1+4b)-5(1-7b)

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Solution for 6b-3+b+1=-5(1+4b)-5(1-7b) equation: 



6b-3+b+1=-5(1+4b)-5(1-7b)

We move all terms to the left:

6b-3+b+1-(-5(1+4b)-5(1-7b))=0

We add all the numbers together, and all the variables

6b+b-(-5(4b+1)-5(-7b+1))-3+1=0

We add all the numbers together, and all the variables

7b-(-5(4b+1)-5(-7b+1))-2=0



We calculate terms in parentheses: -(-5(4b+1)-5(-7b+1)), so:

-5(4b+1)-5(-7b+1)

We multiply parentheses

-20b+35b-5-5

We add all the numbers together, and all the variables

15b-10

Back to the equation:

-(15b-10)



We get rid of parentheses

7b-15b+10-2=0

We add all the numbers together, and all the variables

-8b+8=0

We move all terms containing b to the left, all other terms to the right

-8b=-8

b=-8/-8

b=1

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