6b2+8=404

Solution for 6b2+8=404 equation:

6b^2+8=404

We move all terms to the left:

6b^2+8-(404)=0

We add all the numbers together, and all the variables

6b^2-396=0

a = 6; b = 0; c = -396;
Δ = b2-4ac
Δ = 02-4·6·(-396)
Δ = 9504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9504}=\sqrt{144*66}=\sqrt{144}*\sqrt{66}=12\sqrt{66}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{66}}{2*6}=\frac{0-12\sqrt{66}}{12}
=-\frac{12\sqrt{66}}{12}
=-\sqrt{66}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{66}}{2*6}=\frac{0+12\sqrt{66}}{12}
=\frac{12\sqrt{66}}{12}
=\sqrt{66}
$