6c+(4c-20)=180

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Solution for 6c+(4c-20)=180 equation: 



6c+(4c-20)=180

We move all terms to the left:

6c+(4c-20)-(180)=0

We get rid of parentheses

6c+4c-20-180=0

We add all the numbers together, and all the variables

10c-200=0

We move all terms containing c to the left, all other terms to the right

10c=200

c=200/10

c=20

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