6c+2=(1+4c)

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Solution for 6c+2=(1+4c) equation: 



6c+2=(1+4c)

We move all terms to the left:

6c+2-((1+4c))=0

We add all the numbers together, and all the variables

6c-((4c+1))+2=0



We calculate terms in parentheses: -((4c+1)), so:

(4c+1)

We get rid of parentheses

4c+1

Back to the equation:

-(4c+1)



We get rid of parentheses

6c-4c-1+2=0

We add all the numbers together, and all the variables

2c+1=0

We move all terms containing c to the left, all other terms to the right

2c=-1

c=-1/2

c=-1/2

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