6c+3=1c-12

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Solution for 6c+3=1c-12 equation: 



6c+3=1c-12

We move all terms to the left:

6c+3-(1c-12)=0

We add all the numbers together, and all the variables

6c-(c-12)+3=0

We get rid of parentheses

6c-c+12+3=0

We add all the numbers together, and all the variables

5c+15=0

We move all terms containing c to the left, all other terms to the right

5c=-15

c=-15/5

c=-3

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