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6c+3c=4-5(2c-3)
We move all terms to the left:
6c+3c-(4-5(2c-3))=0
We add all the numbers together, and all the variables
9c-(4-5(2c-3))=0
We calculate terms in parentheses: -(4-5(2c-3)), so:We get rid of parentheses
4-5(2c-3)
determiningTheFunctionDomain -5(2c-3)+4
We multiply parentheses
-10c+15+4
We add all the numbers together, and all the variables
-10c+19
Back to the equation:
-(-10c+19)
9c+10c-19=0
We add all the numbers together, and all the variables
19c-19=0
We move all terms containing c to the left, all other terms to the right
19c=19
c=19/19
c=1
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