6c+3c=4-5(2c-3)

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Solution for 6c+3c=4-5(2c-3) equation: 



6c+3c=4-5(2c-3)

We move all terms to the left:

6c+3c-(4-5(2c-3))=0

We add all the numbers together, and all the variables

9c-(4-5(2c-3))=0



We calculate terms in parentheses: -(4-5(2c-3)), so:

4-5(2c-3)

determiningTheFunctionDomain
-5(2c-3)+4

We multiply parentheses

-10c+15+4

We add all the numbers together, and all the variables

-10c+19

Back to the equation:

-(-10c+19)



We get rid of parentheses

9c+10c-19=0

We add all the numbers together, and all the variables

19c-19=0

We move all terms containing c to the left, all other terms to the right

19c=19

c=19/19

c=1

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