6c-(5c+5)=-8-2(c+12)

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Solution for 6c-(5c+5)=-8-2(c+12) equation: 



6c-(5c+5)=-8-2(c+12)

We move all terms to the left:

6c-(5c+5)-(-8-2(c+12))=0

We get rid of parentheses

6c-5c-(-8-2(c+12))-5=0



We calculate terms in parentheses: -(-8-2(c+12)), so:

-8-2(c+12)

determiningTheFunctionDomain
-2(c+12)-8

We multiply parentheses

-2c-24-8

We add all the numbers together, and all the variables

-2c-32

Back to the equation:

-(-2c-32)



We add all the numbers together, and all the variables

c-(-2c-32)-5=0

We get rid of parentheses

c+2c+32-5=0

We add all the numbers together, and all the variables

3c+27=0

We move all terms containing c to the left, all other terms to the right

3c=-27

c=-27/3

c=-9

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