6c-3(c+1)+2(5-c)=10

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Solution for 6c-3(c+1)+2(5-c)=10 equation: 



6c-3(c+1)+2(5-c)=10

We move all terms to the left:

6c-3(c+1)+2(5-c)-(10)=0

We add all the numbers together, and all the variables

6c-3(c+1)+2(-1c+5)-10=0

We multiply parentheses

6c-3c-2c-3+10-10=0

We add all the numbers together, and all the variables

c-3=0

We move all terms containing c to the left, all other terms to the right

c=3

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