6c-3+10=2(2c-1)+2c

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Solution for 6c-3+10=2(2c-1)+2c equation: 



6c-3+10=2(2c-1)+2c

We move all terms to the left:

6c-3+10-(2(2c-1)+2c)=0

We add all the numbers together, and all the variables

6c-(2(2c-1)+2c)+7=0



We calculate terms in parentheses: -(2(2c-1)+2c), so:

2(2c-1)+2c

We add all the numbers together, and all the variables

2c+2(2c-1)

We multiply parentheses

2c+4c-2

We add all the numbers together, and all the variables

6c-2

Back to the equation:

-(6c-2)



We get rid of parentheses

6c-6c+2+7=0

We add all the numbers together, and all the variables

9!=0

There is no solution for this equation

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